Calendar aptitude problems short cuts
Calendar problems solving tricks - This is one of the reasoning question frequently asked in all the examination. Basically the calendar questions asked to find the leap year, how many days in the year, if first day of month is Tuesday what is the next last day. Very simple calendar problems short cuts is enough to solve this calendar aptitude question with in a 3 minutes. The people who felt that this one is difficult to solve, please see the calendar aptitude tricks formula below and practice it to do well. Firstly we given the calendar problems short cut methods formula, then some solved example are given. Not only that, at end of this post you will find useful calendar problems solving tricks video. But be true, practising this calendar aptitude concepts frequently to become familiar with it, without practising you can't do it faster in the exams.
Important Calendar Aptitude formula :
Odd days - Some question date and month will be given. You have to find the day regarding the given date. For these type of questions you can use odd day concept. Odd day concept is nothing but in the given period of time, number days more than the complete week.
Ordinary year - Only 365 days are present in the Ordinary year.
Leap year - A year which is divisible by 4, but it won't be century. But you have another option that every 4th century should be a leap year. It has 366 days.
Example for Leap year - The years 2004, 1948 are leap years. 2001, 2007, 2005 are not a leap year.
Counting odd days -
Rule 1 - Ordinary year = 365 days. It has 52 weeks plus 1 day. So ordinary years has 1 odd day.
Rule 2 - Leap year = 366 days. Totally 52 weeks plus 2 days. Leap year has two odd days.
Rule 3 - 50 years = 38 ordinary years + 12 leap years
Totally = (38x1 odd day) + 12x2 odd days)
Therefore 62 odd days, then separate it in to weeks.
So 8 weeks+ 6 odd days.
For 50 years there will be a 6 odd days.
Calendar aptitude solve examples :
It was Monday on February 1 2006, find what day will be on 2010 February 1?
Solutions -
On January 31st 2006 is a Tuesday.
No of odd day from year 2006 to 2009 = 5.
So count 5 days after Tuesday, there will be Wednesday, Thursday, Friday, Saturday, Sunday. The day which will come after Sunday, will be Monday this is the day of February 1 2010.
No comments:
Post a Comment